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Code d'Examen: 310-814
Nom d'Examen: SUN (MySQL 5.0, 5.1 and 5.5 Certified Associate Exam)
Questions et réponses: 240 Q&As
Code d'Examen: 310-600
Nom d'Examen: SUN (SUN SIGMA BLACK BELT CERTIFICATION)
Questions et réponses: 100 Q&As
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NO.1 Which of the following statements is correct for equijoin used to join two tables named Employees and
Department?
A. SELECTDept_Name, Emp_Name
FROM Departments d1, Employees e1
ORDER BY Dept_Name, Emp_Name;
B. SELECTD.Dept_Name, E.Emp_Name
FROM Departments d1, Employees e1
HAVING Dept_Name, Emp_Name;
C. SELECTE.Emp_Name,
D. Dept_Name
FROM Departments d1, Employees e1
WHERE Dept_No = Dept_No
ORDER BY Dept_Name, Emp_Name;
E. SELECTDept_Name, Emp_Name
FROM Departments d1, Employees e1
WHERE d1.Dept_No = e1.Dept_No
ORDER BY Dept_Name, Emp_Name;
Answer: D
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NO.2 DRAG DROP
Drag and drop the correct constraint types to their corresponding specifications.
Answer:
NO.3 Which of the following are true about UPDATE statements?
Each correct answer represents a complete solution. Choose all that apply.
A. You can use the WHERE clause to have your update affects a specific set of rows.
B. You use the SET clause to update multiple columns of a table separated by commas.
C. You can use co-related sub query in UPDATE statements to update data from other tables.
D. If you don't use the WHERE clause then the UPDATE will not update any rows in the table.
Answer: A,B,C
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NO.4 You work as a Database Administrator for a company. The company uses MySQL as its database.
You have written two statements, which are as follows:
1. SELECT DISTINCT OBJECT_TYPE
FROM USER_OBJECTS;
2. SELECT OBJECT_TYPE
FROM ALL_OBJECTS;
Which of the following options explains the difference between the results of these two
statements? Each correct answer represents a complete solution. Choose all that apply.
A. The first statement will display distinct object types that can be accessed by the user.
B. The second statement will display all object types that a user can access.
C. The first statement will display distinct object types owned by a user.
D. The second statement will display all object types owned by a user.
Answer: B,C
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NO.5 You work as a Database Administrator for a company. The company uses MySQL as its database.
You want to use group functions, so you have decided to put an alias of group functions as 'GP'.
Which of the following are the correct ways to use group functions?
Each correct answer represents a complete solution. Choose all that apply.
A. GP1(GP2(GPn(group_item))) = result
B. GP1(GP2(group_item)) = result
C. GP1(GP2(GP3(group_item))) = result
D. GP1(group_item) = result
Answer: B,D
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NO.6 Adam works as a Database Administrator for a company. The company uses MySQL as its
database. Adam has created a table named Employees in the database. He wants to retrieve the
information of those employees who have at least one person reporting to them. Which of the
following queries will Adam execute to accomplish the task?
A. SELECTemployee_id, last_name, job_id, department_id FROM Employees WHERE
employee_id
EXISTS (SELECT manager_id WHERE manager_id is NULL);
B. SELECTemployee_id, last_name, job_id, department_id FROM Employees HAVING
employee_id
IN (SELECT manager_id FROM Employees WHERE manager_id is NOT NULL);
C. SELECTemployee_id, last_name, job_id, department_id FROM Employees outer WHERE
EXISTS
(SELECT 'x' FROM Employees WHERE manager_id = outer.employee_id);
D. SELECTemployee_id, last_name, job_id, department_id FROM Employees WHERE
employee_idIN
(SELECT manager_id WHERE manager_id is NOT NULL);
Answer: C
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NO.7 Which of the following provides reliable units of work that allow correct recovery from failures and
keeps a database consistent even in cases of system failure?
A. Database security B.
Two-phase commit C.
Concurrency control
D. Database transaction
Answer: D
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NO.8 Adam works as a Database Administrator for a company. He creates a table named Students. He wants
to create a new table named Class with the help of the Students table. Which of the
following syntaxes will Adam use to accomplish the task?
A. CREATE TABLE Class
INSERT INTO SELECT * FROM Students;
B. CREATE TABLE Class
FROM SELECT * FROM Students;
C. CREATE TABLE Class
(SELECT * FROM Students);
D. CREATE TABLE Class
AS SELECT * FROM Students;
Answer: D
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